What is sin B in a right triangle with AC = 16 and AB = 20?

Question

In triangle ABC, angle C is 90°, AC = 16, and AB = 20. Find sin B.

Answer

sin B = 16/20 = 0.8.

Explanation

Since angle C is a right angle, AB is the hypotenuse. AC is opposite angle B.

The sine of an acute angle is the opposite leg divided by the hypotenuse:

sin B = AC / AB = 16 / 20 = 4/5 = 0.8.

All necessary lengths and labels appear in the statement, so the text alone is sufficient to solve the problem.